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12 January, 10:13

A sample of sodium reacts completely with 0.213 kgkg of chlorine, forming 351 gg of sodium chloride. What mass of sodium reacted?

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Answers (2)
  1. 12 January, 12:25
    0
    The mass of sodium reacted is 138 grams

    Explanation:

    Firstly, the chemical reaction should be represented with a balance chemical equation. The chemical equation can be written as follows.

    Na = sodium

    Cl2 = chlorine gas

    Na + Cl2 → NaCl

    The balanced equation is

    2Na (s) + Cl2 (g) → 2NaCl (aq)

    Atomic mass of sodium = 23 grams per mol

    Atomic mass of chlorine = 35.5 grams per mol

    From the chemical equation the molar mass are as follows

    Sodium = 2 * 23 = 46 grams

    Chlorine = 35.5 * 2 = 71 grams

    Sodium chloride = 2 * 23 + 2 * 35.5 = 117 grams

    if 46 grams sodium reacted to produce 117 grams of sodium chloride

    ? grams of sodium react to produce 351 grams sodium chloride

    grams of sodium reacted = (351 * 46) / 117

    grams of sodium reacted = 16146/117

    grams of sodium reacted = 138 grams
  2. 12 January, 12:36
    0
    0.138 kg of Na.

    Explanation:

    Equation of the reaction

    2Na (aq) + Cl2 (g) - -> 2NaCl (s)

    By stoichiometry, since 2 moles of Na reacted with 1 mole of Cl2 to produce 2 moles of NaCl. Therefore,

    Calculating the number of moles present,

    Cl2:

    Number of moles = mass/molar mass

    Molar mass of Cl2 = 35.5 * 2

    = 71 g/mol.

    = 213 * 71

    = 3 moles.

    NaCl:

    Molar mass = 23 + 35.5

    = 58.5 g/mol.

    Number of moles = mass/molar mass

    = 351/58.5

    = 6 moles.

    Since they both have equal moles,

    Mass of Na = number of moles * molar mass

    Molar mass of Na = 23 g/mol

    = 23 * 6 moles

    = 138 g

    = 0.138 kg of Na.
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