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9 June, 22:29

Determine the oxidation number (oxidation state) of each element in CH 4. C : H : Determine the oxidation number (oxidation state) of each element in SO 2. S : O : Determine the oxidation number (oxidation state) of each element in BF 3. B : F :

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  1. 10 June, 02:03
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    1. In CH₄ molecule:

    The oxidation number of H = ( + 1)

    The oxidation number of C = ( - 4)

    2. In SO₂ molecule:

    The oxidation number of O = ( - 2)

    the oxidation number of S = ( + 4)

    3. In BF₃ molecule:

    The oxidation number of F = ( - 1)

    the oxidation number of B = ( + 3)

    Explanation:

    Oxidation number represents the oxidation state of an element in a given chemical compound, which can be zero, negative or positive.

    The overall charge on a given chemical molecule is equal to sum of the oxidation numbers of all the elements in that molecule.

    Now, calculating the oxidation number-

    1. In CH₄ molecule:

    As we know, the oxidation number of H = ( + 1)

    and the overall charge on the molecule = 0

    Let the oxidation number of C be x

    ∴ x + ( + 1) * 4 = 0

    ⇒ x = ( - 4)

    Therefore, the oxidation number of C = ( - 4)

    2. In SO₂ molecule:

    As we know, the oxidation number of O = ( - 2)

    and the overall charge on the molecule = 0

    Let the oxidation number of S be x

    ∴ x + ( - 2) * 2 = 0

    ⇒ x = ( + 4)

    Therefore, the oxidation number of S = ( + 4)

    3. In BF₃ molecule:

    As we know, the oxidation number of F = ( - 1)

    and the overall charge on the molecule = 0

    Let the oxidation number of B be x

    ∴ x + ( - 1) * 3 = 0

    ⇒ x = ( + 3)

    Therefore, the oxidation number of B = ( + 3)
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