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25 May, 01:22

A solution is prepared at that is initially in chloroacetic acid, a weak acid with, and in potassium chloroacetate. Calculate the pH of the solution. Round your answer to decimal places.

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  1. 25 May, 04:39
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    2.94

    Explanation:

    There is some info missing. I think this is the original question.

    A solution is prepared at 25 °C that is initially 0.38 M in chloroacetic acid (HCH₂ClCO₂), a weak acid with Ka = 1.3 x 10⁻³, and 0.44 M in sodium chloroacetate (NaCH₂CICO₂). Calculate the pH of the solution. Round your answer to 2 decimal places.

    We have a buffer system formed by a weak acid (HCH₂ClCO₂) and its conjugate base (CH₂CICO₂⁻ coming from NaCH₂CICO₂). We can calculate the pH using the Henderson-Hasselbalch equation.

    pH = pKa + log [CH₂CICO₂⁻]/[HCH₂ClCO₂]

    pH = - log 1.3 x 10⁻³ + log (0.44 M/0.38 M)

    pH = 2.94
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