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13 January, 23:27

How many milliliters of a 1:5000 w/v solution of the preservative benzalkonium chloride can be made from 125 mL of a 0.2% w/v solution of the preservative? a. 1250 mL b. 2500 mL C. 625 mL d. 1875 ml

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  1. 14 January, 03:04
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    a. 1250 mL

    Explanation:

    We use the C1V1=C2V2 equation to solve this problem, with:

    C1=1/5000=0,0002 w/v, V1=?

    C2=0,2%=0,2/100=0,002 w/v V2=125 mL

    Then:

    V1=C2V2/C1=0,002*125/0,0002=125O mL

    Thus, 1250 mL of the preservative 1:5000 w/v can be made from 125 mL of a 0,2% w/v solution.
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