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20 November, 00:50

What mass of bromine trifluoride, BrF 3, has the same number of fluorine atoms as 25.0 g of oxygen difluoride, OF2?

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  1. 20 November, 04:36
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    42.29 g of BrF₃.

    Explanation:

    Molar mass of OF2 = 16 + (2 * 19)

    = 54 g/mol

    Number of moles of OF₂ = mass / molar mass

    = 25/54

    = 0.46 mol.

    Number of OF₂ molecules = number of moles * avogadros constant

    = 0.46 * 6.022 x 10²³

    = 2.8 x 10^23 molecules of OF2.

    Since each OF₂ molecule has 2 Fluorine atoms,

    Number of Fluorine atoms in 25.0 g of OF₂ = 2 x 2.8 x 10²³

    = 5.576 x 10²³ atoms of Fluorine.

    Since 1 BrF₃ molecule has 3 Fluorine atoms,

    number of BrF₃ molecules = Number of Fluorine atoms / 3

    = 5.576 x 10²³ / 3

    = 1.8587 x 10²³ molecules of BrF₃.

    Number of moles of BrF₃ = number of molecules of BrF₃ / Avogadros constant

    = (1.8587 x 10²³) / (6.022 x 10²³)

    = 0.30865 moles of BrF₃.

    Molar mass of BrF₃ = 80 + (19 * 3)

    = 137 g/mol

    mass of BrF₃ = number of moles * molar mass

    = 0.30865 * 137

    = 42.29 g of BrF₃.
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