The combustion of ethane (C 2 H 6) (C2H6) produces carbon dioxide and steam. 2 C 2 H 6 (g) + 7 O 2 (g) ⟶ 4 CO 2 (g) + 6 H 2 O (g) 2C2H6 (g) + 7O2 (g) ⟶4CO2 (g) + 6H2O (g) How many moles of CO 2 CO2 are produced when 5.80 mol 5.80 mol of ethane is burned in an excess of oxygen?

There is a production of 11.6 moles of CO₂

Explanation:

The reaction is this:

2C₂H₆ (g) + 7O₂ (g) ⟶ 4CO₂ (g) + 6H₂O (g)

2 moles of ethane reacts with 7 moles of oxygen, to make 4 mol of dioxide and 6 moles of water vapor.

If the oxygen is in excess, we make the calculate with the ethane (limiting reactant)

2 moles of ethane produce 4 moles of dioxide

5.8 moles of ethane produce (5.8.4) / 2 = 11.6 moles