Oxalic acid reacts with sodium hydroxide according to the following equation:
H2C2O4 + 2 NaOH → Na2C20. + 2 H20
A 25.00 mL sample of the H2C2O solution required 19.62 mL of 0.341 M NaOH for
neutralization. Calculate the molarity of the acid.
+3
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Oxalic acid reacts with sodium hydroxide according to the following equation: H2C2O4 + 2 NaOH → Na2C20. + 2 H20 A 25.00 mL sample of the ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Home » Chemistry » Oxalic acid reacts with sodium hydroxide according to the following equation: H2C2O4 + 2 NaOH → Na2C20. + 2 H20 A 25.00 mL sample of the H2C2O solution required 19.62 mL of 0.341 M NaOH for neutralization. Calculate the molarity of the acid.