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24 December, 09:59

Apumpis used toraisethe pressure of a fluid, and it operatesby converting the mechanical shaft work to mechanicalenergyof the fluid flow. A gasoline pump is measured to consume 3.5kW ofmechanical shaftpower when operating. The diameters of the outlet and inlet of the pump are the same and the pressuredifferential between them is 7 kPa. Determine the maximum possible volumeflow rateof gas

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  1. 24 December, 10:06
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    maximum possible volume flow rate = V = 0.5m^3/s

    Explanation:

    Given power consumed = 3.5kW

    pressure difference (delta - P) = 7kPa

    let maximum possible volume flow rate = V

    The rate of flow of work = W = V x Delta - P

    hence, V = W/delta P

    V = 3.5/7

    V = 0.5m^3/s
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