How many moles of sodium hydroxide are required to react completely with 23.1 moles of sulfuric acid

46.2 moles

Explanation:

Since 2 moles of NaOH is required to completely neutralize sulphuric acid to form a normal salt and 1 mole of sulphuric acid is required in the reaction. So if 1 mole of sulphuric acid is 23.1, then 2 moles of NaOH would be 46.2.

A chemical balanced equation is written below

H2SO4 + 2NaOH = Na2SO4 + 2H2O

46. 2 moles of NaOH

Explanation:

Balanced chemical equation between sodium hydroxide and sulfuric acid

2NaOH + H2SO4 = Na2SO4 + 2H2O

I mole of sulphuric acid is neutralized by = 2 moles of NaOH

23.1 mole of sulphuric acid is neutralized by = 2 x 23.1

= 46. 2 moles of NaOH