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1 April, 00:58

What is the molecular formula of the compound with a molecular weight of 112 g/mol and percent composition: 85.6% c and 14.4 % h

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  1. 1 April, 03:37
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    The molecular formula is C8H16

    Explanation:

    Step 1: Data given

    The molecular weight = 112 g/mol

    The compoun contains 85.6 % C and 14.4 % H

    Step 2: Calculate mass of C and H

    Let's consider 100 gram of this compound

    ⇒ 85.6 % of C = 85.6 grams of C

    ⇒ 14.4 % of H = 14.4 grams of H

    Step 3: Calculate moles of C

    Moles C = Mass C / molar mass C

    Moles C = 85.6 grams / 12.0 g/mol

    Moles C = 7.13 mol

    Step 4: Calculate moles of H

    Moles H = 14.4 grams / 1.01 g/mol

    Moles H = 14.3 moles

    Step 5: Calculate the mol ratio

    We divide by the smallest amount of moles

    C: 7.13/7.13 = 1

    H: 14.3 / 7.13 = 2

    The empirical formula is CH2

    The molar mass of the empirical formula is 14.02 g/mol

    Step 6: Calculate the molecular formula

    We have to multiply the empirical formua by n

    n = 112 g/mol / 14.02 g/mol

    n = 8

    The molecular formula is C8H16
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