How many grams of Ca (OH) 2 are needed to produce 600 ml of 1.22 M Ca (OH) 2 solution?

Answer: 54.2 g Ca (OH) 2

Explanation: Molarity is moles of solute / L solution

First convert mL to L

600 mL x 1L / 1000 mL = 0.6 L

Find moles of Ca (OH) 2

n = M x L

= 1.22 M x 0.6 L

= 0.732 moles Ca (OH) 2

Convert moles to mass using its molar mass of Ca (OH) 2 = 74 g

0.732 moles Ca (OH) 2 X 74 g Ca (OH) 2 / 1 mole Ca (OH) 2

= 54.2 g Ca (OH) 2

54.2 g of Ca (OH) ₂

Explanation:

Let's determine the moles of solute, we should need

Molarity. volume (L) = moles

Let's convert 600 mL to L

600 mL / 1000 = 0.6L

1.22 mol/L. 0.6L = 0.732 moles

Finally we must convert the moles to mass (moles. molar mass)

0.732 mol. 74.08 g/mol = 54.2 g