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29 June, 22:26

Uranium can be isolated from its Ores by dissolving it as UO2 (NO3) 2, then separating If as solid UO2 (C2O4).3H2O. Addition of 0.4031 gram of Sodium Oxalate, NaC2O4, to a solution containing 1.481 gram of uranyl nitrate, UO2 (NO2) 2, yields 1.073 gram of solid UO2 (C2O4).3H2O

Na2C2O4 + UO2 (NO3) 2 3H2O? UO2 (C2O4).3H2O + 2NaNO3

determine the limiting reactant and the percent yield of this reaction

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Answers (2)
  1. 29 June, 22:34
    0
    The limiting reactant is NaC₂O₄ and the yield of this reaction is 69.52%.

    Explanation:

    NaC₂O₄ + UO₂ (NO₃) ₂ + 3H₂O → UO₂ (C₂O₄).3H₂O + 2NaNO₃

    m (NaC₂O₄) = 0.4031 g MW = 134 g/mol ∴ n = 3.0 mmol

    m (UO₂ (NO₃) ₂) = 1.481 g MW = 396.05 g/mol ∴ n = 3.74 mmol

    m (UO₂ (C₂O₄).3H₂O) = 1.073 g MW = 412.094 g/mol ∴ n = 2.60 mmol

    The limiting reactant is NaC₂O₄

    The yield can be given by (2.60/3.74).100% = 69.52%
  2. 29 June, 23:53
    0
    Limiting reactant: Na₂C₂O₄

    Percent yield: 86.53%

    Explanation:

    Let's consider the following reaction.

    Na₂C₂O₄ + UO₂ (NO₃) ₂ + 3H₂O → UO₂ (C₂O₄).3H₂O + 2NaNO₃

    The molar mass of Na₂C₂O₄ is 134.0 g/mol and the molar mass of UO₂ (NO₃) ₂ is 394.0 g/mol. In the balanced equation, there is 1 mole of each one.

    The theoretical mass ratio of UO₂ (NO₃) ₂ to Na₂C₂O₄ is 394.0/134.0 = 2.940/1.

    The experimental mass ratio of UO₂ (NO₃) ₂ to Na₂C₂O₄ is 1.481/0.4031 = 3.674/1.

    Comparing the theoretical and the experimental mass ratios, we can see that the reactant in excess is UO₂ (NO₃) ₂ and the limiting reactant is Na₂C₂O₄.

    We will use the limiting reactant to calculate the theoretical yield of UO₂ (C₂O₄).3H₂O. The molar mass of UO₂ (C₂O₄).3H₂O is 412.1 g/mol and the mass ratio of Na₂C₂O₄ to UO₂ (C₂O₄).3H₂O is 134.0g / 412.1g.

    The theoretical yield of UO₂ (C₂O₄).3H₂O is:

    0.4031 g Na₂C₂O₄ * (412.1 g UO₂ (C₂O₄).3H₂O / 134.0 g Na₂C₂O₄) = 1.240 g UO₂ (C₂O₄).3H₂O

    The percent yield is:

    (1.073 g / 1.240 g) * 100% = 86.53%
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