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13 September, 02:06

If 76 grams of Nal are dissolved in enough water to make 225.0 mL of solution, what is the molarity of the solution? (2.25 mol/L)

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  1. 13 September, 05:25
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    2.25 M

    Explanation:

    Molarity of a substance, is the number of moles present in a liter of solution.

    M = n / V

    M = molarity

    V = volume of solution in liter,

    n = moles of solute,

    Moles is denoted by given mass divided by the molecular mass,

    Hence,

    n = w / m

    n = moles,

    w = given mass,

    m = molecular mass.

    From the question,

    w = given mass of Nal = 76 g

    and,

    V = volume of solution = 225.0 mL

    since,

    1 mL = 1 / 1000 L

    V = 225.0 / 1000 L = 0.225 L

    Since,

    we know,

    m = Molecular mass of NaI = 149.89 g / mol

    using, the above formula to calculate the moles,

    n = w / m = 76 g / 149.89 g/mol = 0.507 mol

    now, calculating the molarity as,

    M = n / V = 0.507 mol / 0.225 L = 2.25 M
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