calculate the amount of heat energy required to evaporate 25.7g of water at 100 degrees celcius. (Molar heat of vaporization of liquid water = 4.07x10^4 J/mol)

5.82 * 10⁴ j

Explanation:

Given dа ta:

Mass of water = 25.7 g

Amount of heat to evaporate it = ?

Molar heat of vaporization = 4.07*10⁴ j/mol

Solution:

First of all we will calculate the number of moles of water.

Number of moles = mass / molar mass

Number of moles = 25.7 g / 18 g/mol

Number of moles = 1.43 mol

Energy needed for one mole is 4.07*10⁴ j.

For 1.43 mol:

1.43 mol * 4.07*10⁴ j / 1mol

5.82 * 10⁴ j