1. How many grams would 8.1 x 1021 molecules of sucrose (C12H22011)

weigh?

Mass = 4.6 g

Explanation:

Given dа ta:

Number of molecules of sucrose = 8.1 * 10²¹ molecules

Mass of sucrose = ?

Solution:

First of all we will calculate the number of moles by using Avogadro number.

1 mole * 8.1 * 10²¹ molecules / 6.022*10²³ molecules

1.35 * 10⁻² mol

Mass of sucrose:

Mass = number of moles * molar mass

Molar mass = 342.3 g/mol

Mass = 1.35 * 10⁻² mol * 342.3 g/mol

Mass = 462.1 * 10⁻² g

Mass = 4.6 g