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22 January, 10:18

A student caries out an experiment and dissolves 10.0 g of sodium bromide. NaBr, in 200g of water. What is the molality of the solution?

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  1. 22 January, 13:12
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    0.485mol/kg

    Explanation:

    Molality is defined as the ratio of the number of moles of a solute to the kilogram of a solvent which is usually water.

    Mass of NaBr = 10g

    Molar mass of NaBr = 23+80=103g/mol

    Mole of NaBr = mass / molar mass=10g/103g/mol = 0.097mol

    Molality = Mole of a solute / mass of solvent in kg

    Mole of a solute (NaBr) = 0.097mol; mass of solvent (water in kg) = 200g. To convert to kg: 200g/1000g = 0.2kg

    Molality = 0.097mol/0.2kg = 0.485mol/kg
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