Use the value of the activation energy (Ea=1.50*102kJ/mol) and the given rate constant of the reaction at either of the two temperatures to predict the rate constant at 551 K.

Question

Chemistry

Orion Davidson

13 April, 03:52

Use the value of the activation energy (Ea=1.50*102kJ/mol) and the given rate constant of the reaction at either of the two temperatures to predict the rate constant at 551 K.

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Answers (1)

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Jabari Reynolds · Answer 1

Answer: The rate constant

K = 0.967m-1s-1

Explanation: To calculate the rate constant, we will use the Arrhenius equation.

lnK = ( - Ea/R) (1/T) + lnZ ... (1)

K is the rate constant

Ea is the activation energy

R is the gas constant

T is the temperature in Kelvin

Z is the constant related to the geometry needed, but in this question Z is equal to zero.

Therefore fro data given, we have

Ea = 1.50 * 102kj/mol = 153kj/mol

R = 8.314j/mol-k

T = 551k

Z = 0

Therefore using the equation

lnK = - 153: (8.314 * 551) = - 153 * 4581.014

lnK = - 0.033398719

Taking the ln inverse of K

K = e^ (-0.033398819) = 0.96715286

K = 0.967m-1s-1

This is the rate constant