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6 December, 06:28

What is the ammount if heat in joules required to increase the temperature of a 49.5 gram sample of water from 22c to 66c

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Answers (2)
  1. 6 December, 07:01
    0
    9.1KJ

    Explanation:

    From

    H = mcθ

    m = mass of the water = 49.5g

    c = heat capacity of water = 4.2 Jg-1

    θ = temperature change = (66°C - 22°C) = 44°C

    H = 49.5*4.2*44 = 9.1KJ
  2. 6 December, 08:49
    0
    What is the amount of heat, in joules, required to increase the temperature of a 49.5-gram sample of water from 22°C to 66°C?

    (1) 9100 J (2) 4600 J (3) 1400 J (4) 2300 J

    Answer:

    9100 J is the amount of heat, in joules, required to increase the temperature of a 49.5-gram sample of water from 22°C to 66°C.

    Explanation:

    Given: Q = ? J

    mass = 49.5 g = 0.0495 kg

    T1 = 22°C

    T2 = 66°C

    Cp = 4.18 J/Kg°C

    Q = mCpΔT

    Q = (4.95) (4.18) (66 - 22)

    Q = 9104 J

    So 9100 J is the amount of heat, in joules, required to increase the temperature of a 49.5-gram sample of water from 22°C to 66°C.
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