5.

54g of mercury is heated from 25°C to195°C and absorbs 26110 joules of heat in

the process. Calculate the specific heat capacity of mercury.

2.84 j/g.°C

Explanation:

Given dа ta:

Mass of mercury = 54 g

Initial temperature = 25°C

Final temperature = 195°C

Heat absorbed = 26110 j

Specific heat of mercury = ?

Solution:

Formula:

Q = m. c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

ΔT = 195°C - 25°C

ΔT = 170 °C

Q = m. c. ΔT

c = Q / m. ΔT

c = 26110 j / 54 g. 170 °C

c = 26110 j / 9180 g.°C

c = 2.84 j/g.°C