Ask Question
22 April, 18:06

How long will it take 10.0 mL of Ne gas to effuse through a porous barrier if it has been observed that 125 minutes are required for 10.0 mL of Ar gas to effuse through the same barrier

+5
Answers (1)
  1. 22 April, 21:05
    0
    88.8 minutes

    Explanation:

    Graham's law of diffusion relates rate of difusion by the following formula

    Rate1 / rate 2 = √ (Mass of argon / Mass of Neon)

    Where rate = volume divided by time

    Rate 1 = 10 ml / t1

    Rate 2 = 10 ml / t2

    Rate 1 / rate 2 = 10 ml / t1 : 10 ml / t2 = t2 / t1

    t2/t1 = √ (Mass of argon / mass of Neon) = √ (39.984/20.179)

    125 / t1 = 1.4026

    t1 = 125 / 1.4026 = 88.8 minutes
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “How long will it take 10.0 mL of Ne gas to effuse through a porous barrier if it has been observed that 125 minutes are required for 10.0 ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers