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4 June, 12:19

A chemist prepares a solution of aluminum sulfate (Al2 (SO4) by weighing out 116.0 g of aluminum sulfate into a 450. mL volumetric flask and filing the flask to the mark with water Calculate the concentration in g/dL of the chemist's aluminum sulfate solution. Round your answer to 3 significant digits

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  1. 4 June, 13:39
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    0.0733 mol / dL

    Explanation:

    Mole -

    Moles is denoted by given mass divided by the molecular mass,

    Hence,

    n = w / m

    n = moles,

    w = given mass,

    m = molecular mass.

    From the information of the question,

    w = 116.0 g

    As we know, molecular mass of aluminum sulfate,

    m = 342.15 g/mol

    n = w / m

    n = 116.0 g / 342.15 g/mol = 0.33 mol

    Molarity -

    Molarity of a substance, is the number of moles present in a liter of solution.

    M = n / V

    M = molarity

    V = volume of solution in liter,

    n = moles of solute,

    The unit is mol / L,

    Hence, from the question, the value of molarity is asked,

    From the information of the question,

    V = 450 mL,

    Since,

    1 mL = 0.01 dL

    As, the unit asked in the question is in dL,

    V = 4.5 dL

    n = 0.33 mol (as calculated above)

    Using the above formula,

    M = n / V

    M = 0.33 mol / 4.5 dL

    M = 0.0733 mol / dL

    M =
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