What mass of Neon gas is needed to occupy 2.56 L tube at STP?

Mass = 2.222 g

Explanation:

Given dа ta:

Volume of neon gas = 2.56 L

Temperature = 273 K

Pressure = 1 atm

Mass of neon gas = ?

Solution:

PV = nRT

n = PV / RT

n = 1 atm * 2.56 L / 0.0821 atm. L / mol. K * 273 K

n = 2.56 L. atm / 22.4 atm. L / mol

n = 0.11 mol

Mass = number of moles * molar mass

Mass = 0.11 mol * 20.2 g/mol

Mass = 2.222 g