Ask Question
30 June, 10:32

How many milliliters of 10.0 M HCl (aq) are needed to prepare 790.0 mL of 1.00 M HCl (aq)

+2
Answers (1)
  1. 30 June, 12:37
    0
    79.0 mL

    Explanation:

    Given data

    Initial concentration (C₁) : 10.0 M Initial volume (V₁) : ? Final concentration (C₂) : 1.00 M Final volume (V₂) : 790.0 mL

    In order to find the volume required of the concentrated solution, we will use the dilution rule.

    C₁ * V₁ = C₂ * V₂

    V₁ = C₂ * V₂/C₁

    V₁ = 1.00 M * 790.0 mL/10.0 M

    V₁ = 79.0 mL
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “How many milliliters of 10.0 M HCl (aq) are needed to prepare 790.0 mL of 1.00 M HCl (aq) ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers