Calculate the molarity of a solution prepared by diluting 1.85 L of 6.5 M KOH to 11.0 L.

1.1 M

Explanation:

With this equation:

M1V1 = M2V2

This means, the value of molarity * volume before should be the same as after the dilution

thus:

M1 = 6.5

V1 = 1.85

M2 = ?

V2 = 11.0

Solve for M2:

(6.5 (1.85) = M2 (11.0)

M2 = 1.0932 = 1.1 M

The new molarity of the solution is 1.09 M

Explanation:

Step 1: Data given

Volume of KOH = 1.85 L

Molarity of KOH = 6.5 M

KOH will be diluted to 11.0 L

Step 2: Calculate moles of KOH

Moles KOH = molarity * volume

Moles KOH = 6.5 M * 1.85 L

Moles KOH = 12.025 moles

Step 3: Calculate molarity of the new diluted solution

When we dilute a solution by adding volume, the number of moles will not change.

Molarity = moles / volume

Molarity = 12.025 moles / 11.0 L

Molarity = 1.09 M

The new molarity of the solution is 1.09 M