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6 August, 09:36

The superheated water vapor is at 15 MPa and 350°C. The gas constant, the critical pressure, and the critical temperature of water are R = 0.4615 kPa·m3/kg·K, Tcr = 647.1 K, and Pcr = 22.06 MPa. Determine the specific volume of superheated water based on the ideal-gas equation. (You must provide an answer before moving to the next part)

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  1. 6 August, 12:56
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    0.01917 m^3/kg.

    Explanation:

    Given:

    P = 15 MPa

    = 1.5 * 10^4 kPa

    T = 350 °C

    = 350 + 273

    = 623 K

    Molar mass of water, m = (2 * 1) + 16

    = 18 g/mol

    = 0.018 kg/mol

    R = 0.4615 kPa·m3/kg·K

    Using ideal gas equation,

    P * V = n * R * T

    But n = mass/molar mass

    V = (R * T) / P

    V/M = (R * T) / P * m

    = (0.4615 * 623) / 1.5 * 10^4

    = 0.01917 m^3/kg.
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