How many grams of O2 are needed to react with 18.2 g of NH3?

44 g oxygen are needed.

Explanation:

Given dа ta:

Mass of oxygen needed = ?

Mass of ammonia = 18.2 g

Solution:

Chemical equation:

4NH₃ + 5O₂ → 4NO + 6H₂O

Now we will calculate the number of moles of ammonia:

Number of moles = mass/molar mass

Number of moles = 18.2 g / 17 g/mol

Number of moles = 1.1 mol

Now we will compare the moles of ammonia with oxygen from balance chemical equation.

NH₃ : O₂

4 : 5

1.1 : 5/4*1.1 = 1.375 mol

Mass of oxygen needed:

Mass = number of moles * molar mass

Mass = 1.375 mol * 32 g/mol

Mass = 44 g