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17 October, 20:29

How many grams of O2 are needed to react with 18.2 g of NH3?

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  1. 17 October, 21:54
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    44 g oxygen are needed.

    Explanation:

    Given dа ta:

    Mass of oxygen needed = ?

    Mass of ammonia = 18.2 g

    Solution:

    Chemical equation:

    4NH₃ + 5O₂ → 4NO + 6H₂O

    Now we will calculate the number of moles of ammonia:

    Number of moles = mass/molar mass

    Number of moles = 18.2 g / 17 g/mol

    Number of moles = 1.1 mol

    Now we will compare the moles of ammonia with oxygen from balance chemical equation.

    NH₃ : O₂

    4 : 5

    1.1 : 5/4*1.1 = 1.375 mol

    Mass of oxygen needed:

    Mass = number of moles * molar mass

    Mass = 1.375 mol * 32 g/mol

    Mass = 44 g
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