18 g of copper is mixed with silver nitrate in water. How much copper ll nitrate will formed?

Mass = 112.54 g

Explanation:

Given dа ta:

Mass of copper = 18 g

How much copper (II) nitrate formed = ?

Solution:

Cu + 2AgNO₃ → Cu (NO₃) ₂ + 2Ag

Number of moles of copper:

Number of moles = mass / molar mass

Number of moles = 18 g / 29 g/mol

Number of moles = 0.6 mol

Now we will compare the moles of Cu with Cu (NO₃) ₂.

Cu : Cu (NO₃) ₂

1 : 1

0.6 : 0.6

Mass of Cu (NO₃) ₂:

Mass = number of moles * molar mass

Mass = 0.6 mol * 187.56 g/mol

Mass = 112.54 g