For the reaction 6CO2 (g) + 6H2O (l) > C6H12O6 (s) + 6O2 (g), what mass, in grams, of glucose is produced from 3.00 moles of carbon dioxide?

Mass = 90.1 g

Explanation:

Given dа ta:

Number of moles of carbon dioxide = 3 moles

Mass of glucose produced = ?

Solution:

Chemical equation:

6H₂O + 6CO₂ → C₆H₁₂O₆ + 6O₂

Now we will compare the moles of CO₂ and C₆H₁₂O₆.

CO₂ : C₆H₁₂O₆

6 : 1

3 : 0.5

Mass of glucose:

Mass = number of moles * molar mass

Mass = 0.5 mol * 180.2 g/mol

Mass = 90.1 g