Write the net ionic equation for this precipitation reaction. Include physical states. 2 LiCl (aq) + Pb (CH 3 COO) 2 (aq) ⟶ PbCl 2 (s) + 2 LiCH 3 COO (aq)

2Cl⁻ (aq) + Pb²⁺ (aq) → PbCl₂ (s)

Explanation:

The molecular equation is:

2 LiCl (aq) + Pb (CH₃COO) ₂ (aq) → PbCl₂ (s) ↓ + 2LiCH₃COO (aq)

We identify that a compound that is formed has a different state from the others, so a state change has been produced.

We dissociate all the reactants and the products except for that solid compound

2LiCl (aq) → 2Li⁺ (aq) + 2Cl⁻ (aq)

Pb (CH₃COO) ₂ (aq) → Pb²⁺ (aq) + 2CH₃COO⁻ (aq)

2LiCH₃COO (aq) → 2Li⁺ (aq) + 2CH₃COO⁻ (aq)

We write the complete ionic equation:

2Li⁺ (aq) + 2Cl⁻ (aq) + Pb²⁺ (aq) + 2CH₃COO⁻ (aq) → PbCl₂ (s) + 2Li⁺ (aq) + 2CH₃COO⁻ (aq)

We eliminate the spectators ions, so the net ionic equation is:

2Cl⁻ (aq) + Pb²⁺ (aq) → PbCl₂ (s)