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5 July, 03:56

What is the specific heat of a piece of tin if it measures 36.0g and is heated from 18.0 degrees Celsius. It must absorb 678 j of heat to reach this temperature?

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  1. 5 July, 07:04
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    The answer to your question is C = 1.046 J/g°C

    Explanation:

    Data

    Specific heat = ?

    mass = 36 g

    ΔT = 18°C

    Q = 678 J

    To calculate the specific heat, use the formula of heat and solve it for C

    Formula

    Q = mCΔT

    Solve for C

    C = Q / mΔT

    Substitution

    C = 678 / (36 x 18)

    Simplification

    C = 678 / 648

    Result

    C = 1.046 J/g°C
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