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10 November, 18:34

What volume does 1.954 moles of argon occupy at STP

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  1. 10 November, 18:44
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    Answer: 43.8

    Explanation:

    (1.954 moles Ar) * (22.4 L / 1 moles Ar) = 43.7696 = 43.8 L
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