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17 May, 19:48

The balanced reaction equation for combustion of heptane, C 7 H 16, is C 7 H 16 + 11 O 2 ⟶ 7 CO 2 + 8 H 2 O If the reaction produced 23.5 g CO 2, how many grams of heptane were burned? mass: g C 7 H 16 The reaction of limestone with hydrochloric acid is CaCO 3 + 2 HCl ⟶ CaCl 2 + CO 2 + H 2 O If the reaction produced 23.5 g CO 2, how many grams of HCl reacted? mass: g HCl

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  1. 17 May, 23:44
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    1) There were 7.65 grams of heptane burned

    2) There reacted 38.94 grams of HCl

    Explanation:

    1) The combustion of heptane

    Step 1: Data given

    Mass of CO2 = 23.5 grams

    Molar mass of CO2 = 44.01 g/mol

    Step 2: The balanced equation:

    C7H16 + 11O2 ⟶ 7CO2 + 8H2O

    Step 3: Calculate moles of CO2

    Moles CO2 = mass CO2 / molar mass CO2

    Moles CO2 = 23.5 grams / 44.01 g/mol

    Moles CO2 = 0.534 moles

    Step 4: Calculate moles heptane

    For 1 mole of Heptane, we need 11 moles of O2 to produce 7 moles of CO2 and 8 moles of H2O

    For 0.534 moles of CO2 we have 0.534/7 = 0.0763 moles of heptane

    Step 5: Calculate mass of heptane

    Mass of heptane = moles heptane * molar mass heptane

    Mass heptane = 0.0763 moles * 100.21 g/mol

    Mass heptane = 7.65 grams

    2) The reaction of limestone with hydrochloric acid

    Step 1: Data given

    Mass of CO2 = 23.5 grams

    Step 2: The balanced equation:

    CaCO3 + 2HCl ⟶ CaCl2 + CO2 + H2O

    Step 3: Calculate moles of CO2

    Moles CO2 = mass CO2 / molar mass CO2

    Moles CO2 = 23.5 grams / 44.01 g/mol

    Moles CO2 = 0.534 moles

    Step 4: Calculate moles of HCl

    For 1 mol of CaCO3 we need 2 moles of HCl to produce 1 mol of CaCl2, 1 mol of CO2 and 1 mol of H2O

    For 0.534 moles of CO2 we have 2*0.534 = 1.068 moles of HCl

    Step 5: Calculate mass of HCl

    Mass HCl = moles HCl * molar mass HCl

    Mass HCl = 1.068 moles * 36.46 g/mol

    Mass HCl = 38.94 grams
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