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26 October, 04:21

If 5.61 g of ammonium nitrate (NH4NO3) is dissolved in 155 mL of water to make an instant cold pack, what is the molarity of the resulting solution?

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  1. 26 October, 07:31
    0
    0.452 M

    Explanation:

    Remember that to get molarity, you have to go thru an equation:

    M=mol/V (in liters)

    So ...

    5.61 g NH4NO3 x 1 mol NH4NO3/80.043 g

    =0.0701 mol NH4NO3

    Convert mL to L

    =155--->0.155 L

    Plug in and divide.

    0.0701/0.155

    =0.452 M
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