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21 March, 15:22

The chemical equation below is correctly balanced.

2 SO2 (g) + O2 (g) → 2 SO3 (g)

What is the total number of liters of O2 (g), measured at STP, that will react completely with 4.00 moles of SO2?

A

0.500 L

B

1.00 L

C

22.4 L

D

44.8 L

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Answers (1)
  1. 21 March, 17:50
    0
    44.8 L of O2 will react (option D)

    Explanation:

    Step 1: Data given

    Number of moles of SO2 = 4.00 moles

    STP = Pressure = 1 atm and temperature = 273 K

    Step 2: The balanced equation

    2 SO2 (g) + O2 (g) → 2 SO3 (g)

    Step 3: Calculate moles of O2

    For 2 moles SO2, we need 1 mol O2 to produce 2 moles SO3

    For 4.00 moles SO2 we need 4.00 / 2 = 2.00 moles O2

    Step 4: Calculate volume of O2

    For 1 mol we have a volume of 22.4 L

    V = (n*R*T) / p

    V = (2.00 * 0.08206 * 273) / p

    V = 44.8 L

    For 2.00 moles we have a volume of 2*22.4 = 44.8 L

    44.8 L of O2 will react (option D)
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