4.19-g sample of nitrous oxide (an anesthetic, sometimes called laughing gas) contains 5.73 * 1022 N2O molecules. How many nitrogen atoms?

We have 1.15 * 10^23 nitrogen atoms

Explanation:

Step 1: Data given

Mass of N2O = 4.19 grams

Number of N2O molecules = 5.73 * 10^22 molecules

Molar mass = 44.01 g/mol

Step 2: Calculate moles N2O

Moles N2O = mass N2O / molar mass N2O

Moles N2O = 4.19 grams / 44.01 g/mol

Moles N2O = 0.0952 moles

Step 3: Calculate moles nitrogen

For each mol N2O we have 2 moles of Nitrogen

For 0.0952 moles N2O we have 2*0.0952 = 0.1904 moles nitrogen

Step 4: Calculate atoms nitrogen

Number of nitrogen atoms = moles * number of Avogadro

Number of nitrogen atoms = 0.1904 moles * 6.022*10^23

Number of nitrogen atoms = 1.15 * 10^23 atoms

We have 1.15 * 10^23 nitrogen atoms