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18 October, 23:45

Determine the nuclear composition (number of protons and neutrons) of the following isotopes. (a) chromium-52 protons neutrons (b) selenium-80 protons neutrons (c) molybdenum-98 protons neutrons (d) xenon-132 protons neutrons (e) ytterbium-174 protons neutrons

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  1. 19 October, 02:05
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    Answer: a) chromium-52 : protons = 24, neutrons = 28

    selenium - 80 : protons = 34, neutrons = 46

    molybdenum-98: protons = 42, neutrons = 56

    xenon-132: protons = 54, neutrons = 78

    ytterbium-174 : protons = 70, neutrons = 104

    Explanation:

    Atomic number : It is defined as the number of electrons or number of protons present in a neutral atom.

    Thus, number of protons = atomic number

    Mass number is the number of the entities present in the nucleus which is the equal to the sum of the number of protons and electrons.

    Mass number = Number of protons + Number of neutrons

    a) chromium-52:

    Atomic number of Chromium is 24 hence number of protons = 24

    52 = 24 + Number of neutrons

    Number of neutrons = 28

    b) selenium - 80:

    Atomic number of selenium is 34 hence number of protons = 34

    80 = 34 + Number of neutrons

    Number of neutrons = 46

    c) molybdenum - 98:

    Atomic number of molybdenum is 42 is hence number of protons = 42

    98 = 42 + Number of neutrons

    Number of neutrons = 56

    d) xenon-132:

    Atomic number of xenon is 54 hence number of protons = 54

    132 = 54 + Number of neutrons

    Number of neutrons = 78

    e) ytterbium-174:

    Atomic number of ytterbium is 70 and hence number of protons = 70

    174 = 70 + Number of neutrons

    Number of neutrons = 104
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