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10 February, 04:30

Calculate the pOH of an aqueous solution at 298 K when the hydroxide ion concentration is 3.7 x 10-5 M.

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  1. 10 February, 08:04
    0
    pOH = 4.43

    Explanation:

    pOH = - log[OH⁻] = - log (3.7 x 10⁻⁵) = - (-4.43) = 4.43
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