For any enzyme, what would the initial velocity be, as a percent (%) of Vmax, if the [S] was equal to Km/10?

Question

Chemistry

Jaslene Mason

1 August, 17:51

For any enzyme, what would the initial velocity be, as a percent (%) of Vmax, if the [S] was equal to Km/10?

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Answers (1)

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Carlee Larsen · Answer 1

The initial velocity as a percentage of Vmax is 1100%

Explanation:

From Michaelis Menten equation,

Vo = Vmax[S]/Km+[S]

Vo/Vmax = [S]/Km+[S]

Expressing the initial velocity as a percentage of Vmax is

Vmax/Vo = Km+[S]/[S] * 100

[S] = Km/10

Km = 10[S]

Vmax/Vo = 10[S]+[S]/[S] * 100 = 11[S]/[S] * 100 = 11*100 = 1100%