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11 March, 02:00

The balanced chemical equation for the combustion of propane is

C3H8 (g) + 5O2 (g) →3CO2 (g) + 4H2O (g)

C3 H 8 (g) + 5O2 (g) → 3CO2 (g) + 4H2O (g)

Which statement is correct about the complete combustion of 3.00 mole of propane, C3H8?

a. 12.00 mol H2O are produced.

b. 3.00 g CO2 are produced.

c. 3.00 mol CO2 are produced.

d. 12.00 g H2O are produced.

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Answers (2)
  1. 11 March, 02:27
    0
    Option a. 12.00 mol H2O are produced.

    Explanation:

    C3H8 + 5O2 → 3CO2 + 4H2O

    From equation,

    1mole of C3H8 produce 4moles of H2O.

    Therefore, 3moles of C3H8 will produce = 3 x 4 = 12moles of H2O
  2. 11 March, 05:25
    0
    Option A is correct 12.00 mol H2O are produced.

    Explanation:

    Step 1: Data given

    Number of moles of propane = 3.00 moles

    Step 2: The balanced equation

    C3H8 (g) + 5O2 (g) →3CO2 (g) + 4H2O (g)

    Step 3: Calculate moles

    For 1 mol propane we need 5 moles O2 to produce 3 moles of CO2 and 4 moles H2O

    For 3.00 moles propane we need:

    5*3.00 = 15.00 moles O2

    3*3.00 = 9.00 moles CO2

    4*3.00 = 12.00 moles H2O

    Step 4: Calculate mass

    Mass = moles * molar mass

    Mass H2O = 12.00 mol * 18.02 g/mol

    Mass H2O = 216.2 grams

    Mass CO2 = 9.00 moles * 44.01 g/mol

    Mass CO2 = 396.1 grams

    Option A is correct 12.00 mol H2O are produced.
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