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What volume of 0.500 M AgNO3 are needed to react with 100. mL of 0.400 M K2CrO4? 2 AgNO3 (aq) + K2CrO4 (aq) ➔ Ag2CrO4 (s) + 2 KNO3 (aq)

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  1. Today, 17:45
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    160 mL AgNO3 0.5 M

    Explanation:

    M = mol solute/L solution

    mol solute = M * L solution

    mol solute = (0.400 M * 0.1L) = 0.04 mol K2CrO4

    2 mol AgNO3 - > 1 mol K2CrO4

    x - > 0.04 mol K2CrO4 x = 0.08 mol AgNO3

    L solution = mol solute/M

    L solution = 0.08 mol AgNO3/0.500 M = 0.16 L = 160 mL
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