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9 April, 13:06

If 15.0 liters of neon at 25.0 °C is allowed to expand to 45.0 liters, what must the new temperature be to maintain constant pressure?

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  1. 9 April, 16:42
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    893K=620 °C

    Explanation:

    PV=nRT

    P=nRT/V

    P = (1 mol * 0.0821 * 298K) / 15L P=1.63 atm

    T=PV/nR

    T = (1.63 atm*45 L) / (1 mol*0.0821)

    T = 893K=620 °C
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