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23 January, 07:07

A solution is made by mixing 31 g of heptane C7H16 and 42 g of chloroform CHCl3.

Calculate the mole fraction of heptane in this solution. Round your answer to 2 significant digits.

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Answers (2)
  1. 23 January, 10:09
    0
    The mol fraction of heptane in this solution is 0.47

    Explanation:

    Step 1: Data given

    Mass of heptane = 31.00 grams

    Molar mass of heptane = 100.21 g/mol

    Mass of chloroform = 42.00 grams

    Molar mass of chloroform = 119.38 g/mol

    Step 2: Calculate moles heptane

    moles heptane = 31.00 grams / 100.21 g/mol

    moles heptane = 0.309 moles

    Step 3: Calculate moles chloroform

    moles chloroform = 42.00 grams / 119.38 g/mol

    moles chloroform = 0.352 moles

    Step 4: Calculate total moles

    Total moles = moles heptane + moles chloroform

    Total moles = 0.309 moles + 0.352 moles = 0,661 moles

    Step 5: Calculate mol fraction of heptane

    Mol fraction heptane = moles heptane / total moles

    Mol fraction heptane = 0.309 moles / 0.661 moles

    Mol fraction heptane = 0.47

    The mol fraction of heptane in this solution is 0.47
  2. 23 January, 10:24
    0
    Mole fraction heptane is 0.47

    Explanation:

    To calculate the mole fraction, let's convert mass to mol

    Mass / Molar mass = Mol

    Molar mass heptane = 100 g/m

    31 g/100 g/m = 0.31 moles

    Molar mass chloroform = 119.35 g/m

    42 g / 119.35 g/m = 0.351 moles

    Total moles = 0.31 + 0.351 = 0.661 moles

    Moles of heptane / Total moles = Mole fraction

    0.31 / 0.661 = 0.47
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