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22 December, 18:46

A container has a volume of 200 L at 0.94 atm and 25 C. The pressure changes to 1.00 atm and the temperature changes to 0 C. What is the new volume of the container

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Answers (2)
  1. 22 December, 19:36
    0
    172.23L

    Explanation:

    Data obtained from the question include:

    V1 (initial volume) = 200 L

    P1 (initial pressure) = 0.94 atm

    T1 (initial temperature) = 25°C = 25 + 273 = 298K

    P2 (final pressure) = 1atm

    T2 (final temperature) = 0°C = 0 + 273 = 273K

    V2 (final volume) = ?

    Using the general gas equation P1V1/T1 = P2V2/T2, the final volume of the container can be obtain as follow:

    P1V1/T1 = P2V2/T2

    0.94 x 200/298 = 1 x V2/273

    Cross multiply to express in linear form as shown below:

    298 x V2 = 0.94 x 200 x 273

    Divide both side by 298

    V2 = (0.94 x 200 x 273) / 298

    V2 = 172.23L

    The new volume of the container is 172.23L
  2. 22 December, 22:17
    0
    The answer is going To be 172.23L
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