A container has a volume of 200 L at 0.94 atm and 25 C. The pressure changes to 1.00 atm and the temperature changes to 0 C. What is the new volume of the container

172.23L

Explanation:

Data obtained from the question include:

V1 (initial volume) = 200 L

P1 (initial pressure) = 0.94 atm

T1 (initial temperature) = 25°C = 25 + 273 = 298K

P2 (final pressure) = 1atm

T2 (final temperature) = 0°C = 0 + 273 = 273K

V2 (final volume) = ?

Using the general gas equation P1V1/T1 = P2V2/T2, the final volume of the container can be obtain as follow:

P1V1/T1 = P2V2/T2

0.94 x 200/298 = 1 x V2/273

Cross multiply to express in linear form as shown below:

298 x V2 = 0.94 x 200 x 273

Divide both side by 298

V2 = (0.94 x 200 x 273) / 298

V2 = 172.23L

The new volume of the container is 172.23L

The answer is going To be 172.23L