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24 April, 17:08

If HA, an acid, is 15 percent dissociated in a 2.00 molar solution, what is the Ka for the solution? A. 5.3 * 10-2 B. 6.4 * 10-3 C. 1.1 * 10-2 D. 1.2 * 10-2

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  1. 24 April, 19:06
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    Answer: 0.3

    Explanation:

    We know that

    Ka = [H+] * [A-] / [HA]

    And the acid is 15 % dissociated means that

    [A-] / [HA] * 100 = 15%

    So

    [A-] / [HA] = 0.15

    Then we know that [H+] = [A-] = 2 molar

    Replacing we have

    Ka = 2 molar * 0.15 = 0.3
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