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30 November, 11:05

If we mix 25 grams of sodium bromide with a large amount of potassium chloride, what will our theoretical yield of sodium chloride be?

The equation to solve it is NaBr + KCl - > NaCl + KBr

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  1. 30 November, 11:31
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    Theoretical yield of sodium chloride = 14.04 g

    Explanation:

    Given dа ta:

    Mass of sodium bromide = 25 g

    Theoretical yield of sodium chloride = ?

    Solution:

    Chemical equation:

    NaBr + KCl → NaCl + KBr

    Number of moles sodium bromide:

    Number of moles = Mass / molar mass

    Number of moles = 25.0 g / 102.9 g/mol

    Number of moles = 0.24 mol

    Now we will compare the moles of NaCl with NaBr.

    NaBr : NaCl

    1 : 1

    0.24 : 0.24

    Theoretical yield of sodium chloride:

    Mass = moles * molar mass

    Mass = 0.24 mol * 58.5 g/mol

    Mass = 14.04 g
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