Ask Question
31 May, 21:55

In one experiment, the reaction of 1.00 mercury and an excess of sulfur yielded 1.16g of a sulfide of mercury

What mass remained unreacted in the second experiment?

+1
Answers (1)
  1. 31 May, 22:50
    0
    Answer and Explanation:

    Mercury combines with sulfur as follows -

    Hg + S = HgS

    Hg = 200,59

    S = 32,066 Therefore 1.58 g of Hg will react with -

    1.58 multiply with 32,066 divide by 200,96 of sulfur.

    = 0.25211 g S

    This will form 1.58 + 0.25211 g HgS = 1.83211 g HgS

    The amount of S remaining = 1.10 - 0.25211 = 0.84789 g
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “In one experiment, the reaction of 1.00 mercury and an excess of sulfur yielded 1.16g of a sulfide of mercury What mass remained unreacted ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers