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16 October, 08:38

For some reaction carried out at constant atmospheric pressure and at a constant temperature of 25◦C, it is found that ∆H = - 38.468 kJ/mol and ∆S = + 51.4 J mol · K. What is the value of ∆G for this reaction under these conditions?

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  1. 16 October, 11:04
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    Answer: ΔG = 23.169kJ/mol

    Explanation:

    Solution

    To Calculate Gibbs free energy ΔG for the reaction above we use the equation ΔG=ΔH-TΔS.

    Where

    ΔH = 38.468 kJ/mol = 38468 J/mol

    ∆S = + 51.4 J mol-1 K-1).

    T = 25◦C = 298k

    ΔG = 38468J/mol-298k (51.4 J mol-1 K-1).

    ΔG = 38468 J/mol - 15317.2J/mol

    ΔG = 23168.8J/mol

    ΔG = 23.169kJ/mol
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