A chemist began with 61.5 grams of naclo3. After collecting and drying the product, 30 grams of nacl was obtained. what was the theoretical yield of nacl

Question

Chemistry

Xiomara Hancock

11 July, 13:42

A chemist began with 61.5 grams of naclo3. After collecting and drying the product, 30 grams of nacl was obtained. what was the theoretical yield of nacl

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Answers (1)

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Amaya Novak · Answer 1

33.78 g

Explanation:

NaClO3 decomposes to NaCl and O2 by this reaction:

2NaClO3 - -> 2NaCl + 3O2

Let's determines the mole of chlorate we used (mass / molar mass)

61.5 g / 106.45 g/mol = 0.578 moles.

Ratio is 2:2, so x amount of chlorate will produce x amount of chloride. In conclussion we made 0.578 moles of NaCl from 0.578 moles of chlorate. Let's convert the moles to mass:

0.578 mol. 58.45g/1mol = 33.78 g

That is the theoretical yield of NaCl.