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31 July, 19:35

Na + Br2 - -> NaBr Calculate how many grams of NaBr may be produced from 5.00 grams of solid sodium metal when combined with unlimited Bromine gas.

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  1. 31 July, 22:51
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    22.39g of NaBr

    Explanation:

    First let us write a balanced equation for the reaction. This is illustrated below:

    2Na + Br2 - > 2NaBr

    Molar Mass of Na = 23g/mol

    Mass of Na from the balanced equation = 2 x 23 = 46g

    Molar Mass of NaBr = 23 + 80 = 103g/mol

    Mass of NaBr from the balanced equation = 2 x 103 = 206g

    From the equation,

    46g of Na produced 206g NaBr.

    Therefore, 5g of Na will produce = (5 x 206) / 46 = 22.39g of NaBr
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