Pb (CH3COO) 2 + H2S - -> PbS + CH3COOH 1. How many moles are produced of PbS when 5.00 grams of Pb (CH3COO) 2 is reacted with H2S? Make sure to show your work to get full credit. 2. What type of reaction is shown in the reaction above?

Question

Chemistry

Guest

12 January, 11:55

Pb (CH3COO) 2 + H2S - -> PbS + CH3COOH 1. How many moles are produced of PbS when 5.00 grams of Pb (CH3COO) 2 is reacted with H2S? Make sure to show your work to get full credit. 2. What type of reaction is shown in the reaction above?

+5

Answers (1)

Know the Answer?

Rhianna Welch · Answer 1

1. 0.0154mole of PbS

2. Double displacement reaction

Explanation:

First, let write a balanced equation for the reaction. This is illustrated below:

Pb (CH3COO) 2 + H2S - > PbS + 2 CH3COOH

Molar Mass of Pb (CH3COO) 2 = 207 + 2 (12 + 3 + 12 + 16 + 16) = 207 + 2 (59) = 207 + 118 = 325g

Mass of Pb (CH3COO) 2 = 5g

Number of mole = Mass / Molar Mass

Number of mole of Pb (CH3COO) 2 = 5/325 = 0.0154mole

From the equation,

1mole of Pb (CH3COO) 2 produced 1mole of PbS.

Therefore, 0.0154mole of Pb (CH3COO) 2 will also produce 0.0154mole of PbS

2. The name of the reaction is double displacement reaction since the ions in the two reactants interchange to form two different products